SOLUTION: PLEASE HELP. A store received two shipments of clothing. the cost of the first shipment, which contains 10 sweaters and 20 jackets was $800 . the cost of the second shipment, which
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-> SOLUTION: PLEASE HELP. A store received two shipments of clothing. the cost of the first shipment, which contains 10 sweaters and 20 jackets was $800 . the cost of the second shipment, which
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Question 276384: PLEASE HELP. A store received two shipments of clothing. the cost of the first shipment, which contains 10 sweaters and 20 jackets was $800 . the cost of the second shipment, which contains 5 sweaters and 15 jackets, was $550. find the cost of one sweater and the cost of one jacket. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! :
I assume you are the one that sent this problem to my comment section.
There is no way for me to know for sure, who you are unless you give an email address
;
Anyway here is solution to this problem
:
A store received two shipments of clothing. the cost of the first shipment, which contains 10 sweaters and 20 jackets was $800 . the cost of the second shipment, which contains 5 sweaters and 15 jackets, was $550. find the cost of one sweater
:
Let s = cost of one sweater
Let j = cost of one jacket
:
1st shipment equation
10s + 20j = 800
:
2nd shipment equation
5s + 15j = 550
Put it in a form we can use for substitution
5s = 550 - 15j
divide by 5
s = - j
s = 110 - 3j
:
Replace s with (110-3j) is the 1st shipment equation
10s + 20j = 800
10(110-3j) + 20j = 800
1100 - 30j + 20j = 800
-30j + 20j = 800 - 1100
-10j = -300
j = $30 for jackets
:
We know s = 110-3J
s = 110 - 3(30)
s = 110 - 90
s = $20 for sweaters
:
:
Check solutions in the 2nd shipment equation
5s + 15j = 550
5(20) + 15(30) =
100 + 450 = 550; confirms our solution
