SOLUTION: I need to find the x- and y- intercepts of the graph of the equation: x/3-y/2=1 Thanks in advance for your help.

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Question 263544: I need to find the x- and y- intercepts of the graph of the equation:
x/3-y/2=1
Thanks in advance for your help.

Found 3 solutions by checkley77, hkelly312, Alan3354:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x/3-y/2=1
SETTING X=0 WE GET THE Y INTERCEPT.
0/3-Y/2=1
-Y/2=-
-Y=2
Y=-2 OR (0,-2) IS THE Y INTERCEPT.
SETTING Y=0 WE GET THE X INTERCEPT.
X/3-0/2=1
X/3=1
X=3 0R (3,0) IS THE X INTERCEPT.
THE LINE EQUATION IS:
Y=mX+b WHERE m=THE SLOPE & b=THE Y INTERCEPT.
m=(Y2-Y1)/(X2-X1)
m=(-2-0)/(0-3)
m=-2/-3
m=2/3
Y=2X/3-2 IS THIS LINE EQUATION.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+2x%2F3+-2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -2x/3 -2).

Answer by hkelly312(1) About Me  (Show Source):
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I need to find the x- and y- intercepts of the graph of the equation:
x/3-y/2=1
------------
At the y-int x = 0 and vice versa
----
x/3-y/2=1
0/3-y/2=1
y = -2 --> (0,-2)
-----
x/3-0/2=1
x = 3 --> (3,0)
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Plot the 2 points and draw a line thru them.