SOLUTION: graph the solutions of each linear inequality 4x-y<3 and 3x+4y<12

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Question 263131: graph the solutions of each linear inequality 4x-y<3 and 3x+4y<12
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
4x-y<3
step 1 - subtract 4x to get
-y<-4x+3
step 2 - divide by -1 ; don't for get the negative rule about switching the inequality when multiply or divide by - number. We get
y >4x - 3
here is the graph
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+%3E4x+-+3%29+
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and 3x+4y<12
step 1 - subtract 3x to get
4y<-3x + 12
step 2 - divide by 4 to get
y < (-3/4)x + 3
here is the graph
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+%3C+%28-3%2F4%29x+%2B+3%29+