SOLUTION: in the problem -x - y < 3 how do you get the y to be positive? when put in y = mx + b form for graphing linear inequalities

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Question 251493: in the problem -x - y < 3

how do you get the y to be positive?
when put in y = mx + b form for graphing linear inequalities
Found 2 solutions by richwmiller, checkley77:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
multiply by -1

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
-x - y < 3
-y < x+3 now divide all terms by -1.
y > -x-3 [note: when dividing by a negative value the < sign changes to a > sign].
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-x+-3%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -x -3).