SOLUTION: please help me solve this equation. 2(3+3g)>2g+14

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Question 239053: please help me solve this equation.
2(3+3g)>2g+14
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
2(3+3g)>2g+14

remove parentheses to get:

2*3 + 2*3g > 2g + 14

this becomes:

6 + 6g > 2g + 14

subtract 6 from both sides of the equation to get:

6g > 2g + 14 - 6 which becomes:

6g > 2g + 8

subtract 2g from both sides to get:

4g > 8

divide both sides of the equation by 2 to get:

g > 2

substitute 2 for g in your original equation to confirm the answer is good.

2(3+3g)>2g+14 becomes:

2*(3+3*2) > 2*2+14 which becomes:

2*(3+6) = 4+14 which becomes:

2*9 > 18 which becomes:

18>18 which is false which is good because g was made equal to 2 and g was supposed to be made > 2.

try g = any number > 3 and the equation should be true.

try g = 3

original equation becomes:

2(3+3g)>2g+14 which becomes:

2*(3+3*3) > 2*3 + 14 which becomes:

2*27 > 6+4 which becomes:

54 > 10 which is true.

any value g > 2 should be good.