SOLUTION: I need your help! Thank you so much for your assistance! Graph the system: y>2x+4 y<-x+8

Algebra ->  Graphs -> SOLUTION: I need your help! Thank you so much for your assistance! Graph the system: y>2x+4 y<-x+8      Log On


   



Question 23221: I need your help! Thank you so much for your assistance!
Graph the system:
y>2x+4
y<-x+8

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
I usually shy away from these inequalites, because I don't know how to shade graphs in algebra.com. However, I can graph the lines and you can do the shading for me.

First graph y = 2x + 4, which is a straight line with y-intercept up 4 units on the y-axis, and a slope of 2.

Because the inequality is ">" you do NOT want to include the line, so graph it with a DOTTED line, and since it is "y> ___" you must shade ABOVE the line.

graph%28300%2C300%2C+-10%2C10%2C-10%2C10%2C+2x%2B4+%29+


For the next one, graph y = -x + 8, which is a straight line with y-intercept up 8 units on the y-axis, and a slope of -1.

Because the inequality is "<" you do NOT want to include the line, so graph it with a DOTTED line, and since it is "y< ___" you must shade BEWLOW the line.

graph%28300%2C300%2C+-10%2C10%2C-10%2C10%2C+-x%2B8+%29+

Now, do it all together on one graph. Remember both lines are to be dotted, and shade above the first line, and below the second line. It should look like this:
graph%28300%2C300%2C+-10%2C10%2C-10%2C10%2C+2x%2B4%2C+-x%2B8+%29+
In my graph, remember, BOTH lines are DOTTED, and shade ABOVE the red line, and below the green line. The solution is the INTERSECTION of the two areas-- that is the area common to both, the overlapping area, in this case, the upper left part of the graph.

R^2 at SCC