Question 225395: please help me find the y intercept and x intercept for this equation; 16y-4x=-8
Found 3 solutions by scott8148, rfer, RAY100:
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! when the graph crosses the y-axis (y-intercept), the value of x is zero
___ so 16y = -8 and y = -1/2, making the intercept (0, -1/2)
similarly, when the graph crosses the x-axis (x-intercept), the value of y is zero
___ so -4x = -8 and x = 2, making the intercept (2, 0)
Answer by rfer(16322)  (Show Source):
Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website! 16y -4x =-8
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x intercept is @y=0,,,,,16(0) -4x =-8,,,,x=2
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y intercept is @ x=0,,,,,16y -4(0) =-8,,,,,y= - 8/16 = -1/2
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check,,,,16y -4x =-8,,,,,16y = 4x -8,,,,y= 1/4 *x - 1/2,,,,yintercept = - 1/2
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(2,0) ,,,,,16*0 -4(2) =-8,,,ok
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(0,-1/2),,,,,,16*-1/2 -4(0) = -8,,,,,ok
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