SOLUTION: How do I graph a line using the slope of m=1/3 and point (3,-1)?

Question 223927: How do I graph a line using the slope of m=1/3 and point (3,-1)?
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
How do I graph a line using the slope of m=1/3 and point (3,-1)?
Step 1. The slope m is given as

Step 2. Let (x1,y1)=(3,-1) or x1=2 and y1=1 . Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.

Step 3. Now we're given . Substituting above values and variables in the slope equation m yields the following steps:

Step 4. Multiply x-3 to both sides to get rid of denominator on right side of equation.

Step 5. Now add -1 to both sides of equation to solve for y.

The slope m=1/3 and y-intercept is -2 at point (0,-2).

Now you have two points (0,-2) and (3,-1) to draw a line.

Note: the above equation can be rewritten as
Note in this form: when y=0 then x=6 at point (6,0).

And the graph is shown below which is consistent with the above steps.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .

X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 2/0.333333333333333 = 6.00000000000001.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 2/-1 = -2.
Slope is -0.333333333333333/-1 = 0.333333333333333.
Equation in slope-intercept form: y=0.333333333333333*x+-2.

I hope the above steps were helpful. Good luck in your studies!

Respectfully,
Dr J

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.

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