SOLUTION: Graph the equation using the slope and the y-intercept. y=9/7x + 5 Use the graphing tool to graph the line. Use the slope and y-intercept when drawing the line.

Algebra ->  Graphs -> SOLUTION: Graph the equation using the slope and the y-intercept. y=9/7x + 5 Use the graphing tool to graph the line. Use the slope and y-intercept when drawing the line.      Log On


   



Question 222379: Graph the equation using the slope and the y-intercept.
y=9/7x + 5
Use the graphing tool to graph the line. Use the slope and y-intercept when drawing the line.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=%289%2F7%29%2Ax%2B5 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-7

y=%289%2F7%29%2A%28-7%29%2B5

y=-63%2F7%2B5 Multiply

y=-28%2F7 Add

y=-4 Reduce

So here's one point (-7,-4)




Now lets find another point

Plug in x=0

y=%289%2F7%29%2A%280%29%2B5

y=0%2F7%2B5 Multiply

y=35%2F7 Add

y=5 Reduce

So here's another point (0,5). Add this to our graph





Now draw a line through these points

So this is the graph of y=%289%2F7%29%2Ax%2B5 through the points (-7,-4) and (0,5)


So from the graph we can see that the slope is 9%2F7 (which tells us that in order to go from point to point we have to start at one point and go up 9 units and to the right 7 units to get to the next point) the y-intercept is (0,5)and the x-intercept is (-3.88888888888889,0) ,or (-35%2F9,0)


We could graph this equation another way. Since b=5 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,5).


So we have one point (0,5)





Now since the slope is 9%2F7, this means that in order to go from point to point we can use the slope to do so. So starting at (0,5), we can go up 9 units



and to the right 7 units to get to our next point


Now draw a line through those points to graph y=%289%2F7%29%2Ax%2B5


So this is the graph of y=%289%2F7%29%2Ax%2B5 through the points (0,5) and (7,14)