SOLUTION: find the standard form of the equation of the circle with the endpoints of the diameter at the points of (5,2) and (-9,6)
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Question 215740: find the standard form of the equation of the circle with the endpoints of the diameter at the points of (5,2) and (-9,6) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! find the standard form of the equation of the circle with the endpoints of the diameter at the points of (5,2) and (-9,6)
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The diameter is the distance between the 2 points.
d^2 = diffy^2 + diffx^2 = 4^2 + 14^2
d^2 = 212
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The center is the midpoint. Find the average of x and y separately.
x: (5-9)/2 = -2
y: (2+6)/2 = 4
Center at (2,-4)
(x-2)^2 + (y-4)^2 = 212 is the circle
