SOLUTION: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x+3y=6 and passing though (-3,5)

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Question 209092: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x+3y=6 and passing though (-3,5)
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
A line perpendicular to x+3y=6 and passing though (-3,5)
4y=-x+6
y=-x/4+6/4
y=-x/4+1.5 (red line)
this line has a slope=-1/4.
A perpendicular line has a slope=4
Y=mX+b
5=4*-3+b
5=-12+b
b=5+12
b=17 the y intercept.
y=4x+17 (green line) is the equation for the perpendicular line passing through (-3,5)
+graph%28+300%2C+300%2C+-20%2C+20%2C+-20%2C+20%2C+-x%2F4+%2B1.5%2C+4x+%2B17%29+ (graph 300x300 pixels, x from -20 to 20, y from -20 to 20, of TWO functions -x/4 +1.5 and 4x +17).