SOLUTION: how do I graph 2x-4y=8 using x and y intercepts?

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Question 205674: how do I graph 2x-4y=8 using x and y intercepts?
Found 2 solutions by Targetweek, Theo:
Answer by Targetweek(62) About Me  (Show Source):
You can put this solution on YOUR website!
this should explain it pretty well
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 2+x+%2B+-4+y+=+8 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-2%2F-4.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 8/2 = 4.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 8/-4 = -2.
  • Slope is -2/-4 = 0.5.
  • Equation in slope-intercept form: y=0.5*x+-2.
graph%28+500%2C+500%2C+4-8%2C+4%2B8%2C+-2-8%2C+-2%2B8%2C+0.5%2Ax%2B-2+%29+


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
2x - 4y = 8
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your y intercept is when x = 0, so make x = 0 and solve for y.
- 4y = 8
y = 8/-4
y = -2
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your x intercept is when y = 0, so make y = 0 and solve for x.
2x = 8
x = 4
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you have 2 points on your line.
1 point is (0,-2)
the other point is (4,0)
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you still need to have an equation though.
for graphing purposes you need to solve for y.
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your equation is:
2x - 4y = 8
add 4y to both sides and subtract 8 from both sides to get:
2x - 8 = 4y
divide both sides by 4 to getr:
y = .5x - 2
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once again, your y intercept is when x = 0, so y intercept = -2
this confirms what we got earlier.
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once again, your x intercept is when y = 0, so equation becomes:
0 = .5x - 2
add 2 to both sides to get:
2 = .5x
divide both sides by .5 to get:
4 = x
or
x = 4
this also confirms what we got earlier.
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graph of your equation will look like this:
graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C.5x-2%29