SOLUTION: Could you please help me out? Find an equation of the line having the given slope and containing the given point. m=7/8, (5,-2) The equation of the line is y = Thanks for y

Algebra ->  Graphs -> SOLUTION: Could you please help me out? Find an equation of the line having the given slope and containing the given point. m=7/8, (5,-2) The equation of the line is y = Thanks for y      Log On


   

Question 202960: Could you please help me out?
Find an equation of the line having the given slope and containing the given point. m=7/8, (5,-2)
The equation of the line is y =
Thanks for your help!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 7%2F8 which goes through the point (5, -2), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y--2=%287%2F8%29%28x-5%29 Plug in m=7%2F8, x%5B1%5D=5, and y%5B1%5D=-2 (these values are given)


y%2B2=%287%2F8%29%28x-5%29 Rewrite y--2 as y%2B2


y%2B2=%287%2F8%29x%2B%287%2F8%29%28-5%29 Distribute 7%2F8


y%2B2=%287%2F8%29x-35%2F8 Multiply 7%2F8 and -5 to get -35%2F8


y=%287%2F8%29x-35%2F8-2 Subtract 2 from both sides to isolate y


y=%287%2F8%29x-51%2F8 Combine like terms -35%2F8 and -2 to get -51%2F8 (note: if you need help with combining fractions, check out this solver)


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Answer:


So the equation of the line with a slope of 7%2F8 which goes through the point (5, -2) is:

y=%287%2F8%29x-51%2F8 which is now in y=mx%2Bb form where the slope is m=7%2F8 and the y-intercept is b=-51%2F8