SOLUTION: can't figure out how to solve problems like 2x+6y=12 finding three ordered pairs, I don't know where to begin

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Question 198017This question is from textbook Intregrated arithmetic and basic algebra
: can't figure out how to solve problems like 2x+6y=12 finding three ordered pairs, I don't know where to begin This question is from textbook Intregrated arithmetic and basic algebra

Found 2 solutions by solver91311, scott8148:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

What you want to find are three ordered pairs so that when you replace and in the equation with the values from the ordered pair, you have a true statement.

Step 1. Pick a value for . It can be any real number, so pick a small integer -- it makes the arithmetic easier. Zero is a nice round number (so to speak), so let's pick zero for our first try.

Step 2. Substitute the selected number into the equation in place of the .



Step 3. Solve for :



Step 4. Create your ordered pair from the selected value of and the calculated value of



Step 5. Check your work:



Checks.

Perform steps 1 through 5 twice more using a new value for each time. Done.

John


Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the equation is a straight line --- 1st order in x and y (both to the 1st power)

the 3 "ordered pairs" are just 3 points on the line

pick values for x (or y) and then use the equation to find the corresponding value for the other variable
___ these pairs of values are "ordered"



HINT: zeros are easy to work with
___ and maybe a 1 for y ...