SOLUTION: Find the vertex and intercepts of the function : f(x)=x^2+x-2 This is what I have, is it correct if not, please explain/show. Vertex: (-1 -18) ; Intercepts: (-2,0)(1,0)(0,

Algebra ->  Graphs -> SOLUTION: Find the vertex and intercepts of the function : f(x)=x^2+x-2 This is what I have, is it correct if not, please explain/show. Vertex: (-1 -18) ; Intercepts: (-2,0)(1,0)(0,      Log On


   

Question 192082This question is from textbook Intermediate Algebra, Applied Approach
: Find the vertex and intercepts of the function : f(x)=x^2+x-2
This is what I have, is it correct if not, please explain/show.
Vertex: (-1 -18) ; Intercepts: (-2,0)(1,0)(0,2) This question is from textbook Intermediate Algebra, Applied Approach

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%28x%5E2%2Bx%2B%281%2F4%29%29-1%2F4-2 complete the square by adding and subtracting 1/4
:
f%28x%29=%28x%2B1%2F2%29%5E2-%289%2F4%29
:
vertex is (-1/2,-9/4)
:
to find y intercept set x to zero y=0^2+0-2=-2 : (0,-2)
:
to find x intercept set y to zero 0=x%5E2%2Bx-2
:
%28x%2B2%29%28x-1%29=0
:
x=-2 or 1