SOLUTION: Soybean meal in 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 10% protein?

Algebra ->  Graphs -> SOLUTION: Soybean meal in 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 10% protein?      Log On


   



Question 185934: Soybean meal in 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 10% protein?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let s= pounds of soybean meal needed
Let c= pounds of cornmeal needed
given:
.16s= pounds of protein in soybean meal needed
.08c= pounds of protein in cornmeal needed
320= pounds of final mixture
--------------
(1) %28.16s+%2B+.08c%29%2F320+=+.1
(2) s+%2B+c+=+320
Multiply both sides of (1) by 320
(1) .16s+%2B+.08c+=+.1%2A320
(1) .16s+%2B+.08c+=+32
Multiply both sides of (2) by .08
(2) .08s+%2B+.08c+=+25.6
Subtract (2) from (1)
(1) .16s+%2B+.08c+=+32
(2) -.08s+-+.08c+=+-25.6
(3) .08s+=+6.4
(3) s+=+80
and
(2) s+%2B+c+=+320
(2) 80+%2B+c+=+320
(2) c+=+240
80 pounds of soybean meal and 240 pounds of cornmeal
are needed
check:
(1) %28.16%2A80+%2B+.08%2A240%29%2F320+=+.1
(1) %2812.8+%2B+19.2%29%2F320+=+.1
(1) 32%2F320+=+.1
(1) .1+=+.1
OK