SOLUTION: Find the equation, in standard form, of the line perpendicular to 2x - 3y = -5 and passing through (3, -2). Write the equation in standard form, with all integer coefficients.

Algebra ->  Graphs -> SOLUTION: Find the equation, in standard form, of the line perpendicular to 2x - 3y = -5 and passing through (3, -2). Write the equation in standard form, with all integer coefficients.       Log On


   

Question 179342This question is from textbook
: Find the equation, in standard form, of the line perpendicular to 2x - 3y = -5 and passing through (3, -2). Write the equation in standard form, with all integer coefficients.
What equation do you use to solve this?
I was trying y-y1=m(x-x1) This question is from textbook

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First off, find the slope of your first line.
Re-arrange it into slope intercept form,
y=m%5B1%5D%2Ax%2Bb
Then find the slope of the second line, using the slope relationship of perp. lines,
m%5B1%5Dm%5B2%5D=-1
Then use the point slope form,
y-y%5Bp%5D=m%5B2%5D%28x-x%5Bp%5D%29
y%2B2=m%5B2%5D%28x-3%29
Then re-arrange so that you have no denominators and x and y are on the left hand side, constants on the right hand side.
Repost if you need more help or get stuck.