SOLUTION: One plane left New York headed to Tokyo flying at an average speed of 375 mi/h. Another plane left New York 1 h. later following the same route and flying at an average speed of 50
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Question 17674: One plane left New York headed to Tokyo flying at an average speed of 375 mi/h. Another plane left New York 1 h. later following the same route and flying at an average speed of 500 mi/h. If both planes followed the same course, how many hours after it left New York would the second plane catch up to the first plane?
Write an equation you could solve to answer the question. Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! Let x = time of the second plane flying at 500 mph.
x+1 = time of the first plane flying at 375 mph.
Distance of first plane = Distance of second plane
R*T = R*T
500x = 375(x+ 1)
500x = 375x + 375
500x - 375x = 375x - 375x + 375
125x = 375 hours = time for second plane to catch the first plane.
Check:
Distance of first plane = 4 *375= 1500 miles
Distance of second plane = 3*500 = 1500 miles
