Question 174356: Find an equation of the line that is parallel to the line y=-4/3x+7 and that passes through the point (7,3). Found 2 solutions by Mathtut, stanbon:Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! lines that are parallel have equal slopes so the slope of the line we are looking for has a slope of -4/3
:
using the point slope formula
:
y-3=-4/3(x-7)
:
y-3=-4/3(x)+28/3......multiply terms by 3
:
3y-9=-4x+28
:
You can put this solution on YOUR website! Find an equation of the line that is parallel to the line y=-4/3x+7 and that passes through the point (7,3).
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The slope is -4/3; you ned to find the y-intercept.
Form: y = mx + b
3 = (-4/3)*7 + b
-3 = -28/3 + b
-9/3 = -28/3 + b
b = 19/3
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Equation:
y = (-4/3)x + (19/3)
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Cheers,
Stan H.
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