SOLUTION: Graph on a plane. 2x+3y<=6 I am confused by this one as well, would I change the inequality to just an equal sign then change it into the y=mx+b formula?

Algebra ->  Graphs -> SOLUTION: Graph on a plane. 2x+3y<=6 I am confused by this one as well, would I change the inequality to just an equal sign then change it into the y=mx+b formula?      Log On


   

Question 174022: Graph on a plane.
2x+3y<=6
I am confused by this one as well, would I change the inequality to just an equal sign then change it into the y=mx+b formula?
Found 2 solutions by Mathtut, solver91311:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
you can graph this no matter what form its in. Just start plotting x and y values.
if x =1 then y= ...2(1)+3y=6... 3y=4...so y=4/3 do this for several value of x
remember when graphing to include the inequality.
once you have a graph try a couple of points on either side to see if they meet the criteria of the inequality . Then you will know what to color in for your answer. you should end up with everthing colored in below the line.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-2%2F3%29x%2B2%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Step 1: Change the inequality sign to an equal sign and graph the resulting line by whatever method you like. Since the inequality sign includes equals (≤), graph the line as a solid line. (otherwise, you would graph it as a dashed line.)

Step 2: Pick a point that is NOT on the line. Any time you have a line that does NOT pass through the origin, pick (0,0) as your point.

Step 3: Substitute the coordinate values from the point you selected into the original inequality.

If the result is a TRUE statement, shade in the half-plane on the side of the line that CONTAINS the selected point.

If the result is a FALSE statement, shade in the half-plane on the side of the line that does NOT CONTAIN the selected point.