SOLUTION: The equation of the line parallel to the line whose equation is 2x+y=0 and passing through the point P(1,-3) is _______

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Question 173513This question is from textbook Essentials Algebra
: The equation of the line parallel to the line whose equation is 2x+y=0 and passing through the point P(1,-3) is ________ . This question is from textbook Essentials Algebra

Found 2 solutions by Mathtut, Alan3354:
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website!
lines that are parallel have equal slopes. we need to write this equation in y=mx+b format to easily spot the slope m
:
y=-2x+0...so slope is -2
:
now we use the point slope formula
:
y-(-3)=-2(x-1)
:
y+3=-2x+2
:

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
The equation of the line parallel to the line whose equation is 2x+y=0 and passing through the point P(1,-3) is ________
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Parallel lines have the same slope.
Find the slope of the line by putting it into slope-intercept form.
2x+y=0
y = -2x
The slope, m, = -2
Then,
y-y1 = m*(x-x1) where (x1,y1) is the point (1,-3)
y+3 = -2(x-1)
y+3 = -2x+2
y = -2x - 1 slope-intercept form
2x+y = -1 standard form

SOLUTION: The equation of the line parallel to the line whose equation is 2x+y=0 and passing through the point P(1,-3) is ________ .