Question 170365: I need help with a fairly simple equation that i just don't understand.
It's in pointY=A+B(X) form. I am given two sets of points which are, (-1,-6) and(4,8)
I tried -1+-6(4)=8 which obviously doesn't work.
Then I tried -6=2+=1(8) but there is no two in the equation, or am I trying to get a new number?
(-1,-6)(4,8)
in
Y=A+BX form.
Found 2 solutions by checkley77, Mathtut:
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! THE LINE FORMULA IS:
Y=mX+b WHERE m=SLOPE & b=Y INTERCEPT.
SLOPE=(Y2-Y1)/(X2-X1)=(8+6)/(4+1)=14/5 SLOPE
NOW REPLACE THE X & Y TERMS WITH ONE SET OF (X,Y) POINTS & SOLVE FOR THE Y INTERCEPT b.
-6=-1*14/5+b
-6=-14/5+b
b=-6+14/5
b=(-6*5+14)/5
b=(-30+14)/5
b=-16/5 Y INTERCEPT.
Y=14X/5-16/5 ANS FOR THE LINE EQUATION.
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 14x/5 -16/5).
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! you need to find the slope which is change in y over the change in x or rise/run
slope for points (-1,-6) and (4,8) is (8-(-6))/(4-(-1))=14/5
now standard equation for point slope is y-k=m(x-h) where m is the slope and (h,k) is any point on the line.
I will be using point (4,8)
:
y-8=(14/5)(x-4)
:
y-8=14/5(x)-56/5--->multiply all terms by 5
:
5y-40=14x-56--->write in standard form
:
 is the equation with points (-1,-6) and (4,8)
y=mx+b format would be y=(14/5)x-16/5
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