SOLUTION: I need help on finding an equation of the line having given the slope and containing the given points. Here is the equation: m=6/7,(6, -3)

Algebra ->  Graphs -> SOLUTION: I need help on finding an equation of the line having given the slope and containing the given points. Here is the equation: m=6/7,(6, -3)      Log On


   

Question 168976: I need help on finding an equation of the line having given the slope and containing the given points.
Here is the equation:
m=6/7,(6, -3)
Found 2 solutions by josmiceli, checkley77:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The straight-line equation in the slope-intercept
form is y+=+mx+%2B+b, where
m= slope
b= the y-intercept
--------------
The problem gives
m+=+6%2F7
and the line passes through (6, -3)
If I plug in the value for slope,
y+=+%286%2F7%29%2Ax+%2B+b
Since (6,-3) is a solution for the equation, I can say
-3+=+%286%2F7%29%2A6+%2B+b
Multiply both sides by 7
-21+=+36+%2B+7b
7b+=+-21+-36
7b+=+-57
b+=+-%2857%2F7%29
y+=+%286%2F7%29%2Ax+-+%2857%2F7%29
Multiply both sides by 7
7y+=+6x+-+57 answer
check:
Does it pass through (6,-3)?
7%2A%28-3%29+=+6%2A6+-+57
-21+=+36+-+57
-21+=+-21
OK

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Y=mX+b
-3=6/7*6+b
-3=36/7+b
b=-3-36/7
b=(-3*7-36)/7
b=(-21-36)/7
b=-57/7 the y intercept.
y=6x/7-57/7 ans.
+graph%28+300%2C+200%2C+-6%2C+15%2C+-10%2C+10%2C+6x%2F7+-57%2F7%29+ (graph 300x200 pixels, x from -6 to 15, y from -10 to 10, 6x/7 -57/7).