Question 168961: I don't understand how to do this problem?
3x+y=5
-2x+3y=4
Found 3 solutions by josmiceli, stanbon, Electrified_Levi: Answer by josmiceli(19441) (Show Source): Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 3x+y=5
-2x+3y=4
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Multiply thru the 1st equation by 3:
9x+3y = 15
-2x+3y = 4
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Subtract the 2nd from the 1st to get:
11x = 11
X = 1
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Substitute this into 3x+y=5 to solve for "y":
3*1 + y = 5
y = 2
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Ans: (1,2)
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Cheers,
Stan H.
Answer by Electrified_Levi(103) (Show Source):
You can put this solution on YOUR website! Hi, Hope I can help,
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3x+y=5
-2x+3y=4
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There are several ways to solving these systems of equations, I will show you an overall easy way of doing it
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First, solve for a letter, usually the easiest one, we will solve for "y" in both equations
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First equation, , we need to move "3x" to the right side
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= = or , if we rearrange it.
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Our first answer is 
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Let us solve for "y" in the second equation, 
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, first we need to move (-2x) to the right side
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= = or , rearranging it
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, now we need to divide each side by "3" to get "y"
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= = 
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is our second answer
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Since "y" equals one number both of our answers will equal each other
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First answer = 
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Second answer = 
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These two answers will equal each other
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= , we will use cross- multiplication
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= 
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, rearranging the left side
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, now we can use the distribution method
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= 
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Remember the negative and positive signs
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Now we can solve for "x", let us move (-9x) to the right side
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= = , now we need to move "4" to the left side
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= = , now we can divide each side to find "x"
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= = , , you can check by replacing "x" with "1" in the equation 
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= = = = ( True )
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, to find "y", replace "x" with "1" in one of the two original equations
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3x+y=5
-2x+3y=4
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We will use the first equation
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= = , now we will move "3" to the right side
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= 
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.

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We can check our answers by replacing both "x" and "y" in the two original equations. ( x = 1 ) ( y = 2 )
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= = = ( True )
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= = = ( True )
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A solution set is in the form (x,y), our solution set is ( 1, 2 )
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Hope I helped, Levi
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