SOLUTION: I really need help on this one. My book has me confused. find the equation of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1). Write the equation in standa

Algebra ->  Graphs -> SOLUTION: I really need help on this one. My book has me confused. find the equation of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1). Write the equation in standa      Log On


   



Question 167021: I really need help on this one. My book has me confused.
find the equation of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1). Write the equation in standard form, with all integer coefficients.
Thanks if you can help.

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Let's get this line 1st: 3x+%96+4y+=+9
We can follow the eqn thru the SLope Intercept form, y=mx%2Bb
4y=3x-9 Divide whole eqn by 4
cross%284%29y%2Fcross%284%29=%283%2F4%29x-%289%2F4%29---> slope (m)=3/4, and y-intercept(b) = -9/4
f(y)=0: Then,
0=3x-9
3x=9 --> cross%283%29x%2Fcross%283%29=cross%289%293%2Fcross%283%29
x=3
We have points (3,-9/4) for this line. We see the graph,
-- see points (3,-9/4)
Now, we'll see the line that passes thru (-2,-1) & perpendicular to above line:
By y=mx%2Bb, and since it's perpendicular, the slope, m%5B2%5D=-1%2Fm%5B1%5D=-1%2F%283%2F4%29=-4%2F3
Continuing,
-2=%28-4%2F3%29%28-1%29%2Bb
-2=%284%2F3%29%2Bb
b=-2-4%2F3=%28-6-4%29%2F3
b=-10%2F3 ----> y-intercept
Therefore, getting this y intercept ( we'll need it in the graph of course), your line eqn ---> y=%28-4%2F3%29x-%2810%2F3%29
Simplifying if you want,
highlight%28%284%2F3%29x%2By=-10%2F3%29, Or, Multiply whole eqn by 3:
cross%283%29%284%2Fcross%283%29%29x%2B3y=cross%283%29%28-10%2Fcross%283%29%29
highlight%284x%2B3y=-10%29 ANSWER
See the graph,
---> see the RED line, it DOES NOT PASS on (-2,-1) BUT RATHER ON POINTS (-1,-2)as shown again:
---> RED Line %28-4%2F3%29x-10%2F3: GREEN Line 3x-4y=9
Thank you,
Jojo