SOLUTION: One day a vendor runs out of cups in which to sell soda. Before the vendor runs out of cups, the vendor sold large sodas for $0.70 each and small sodas for $0.50 each. The vendor k

Algebra ->  Graphs -> SOLUTION: One day a vendor runs out of cups in which to sell soda. Before the vendor runs out of cups, the vendor sold large sodas for $0.70 each and small sodas for $0.50 each. The vendor k      Log On


   



Question 166561: One day a vendor runs out of cups in which to sell soda. Before the vendor runs out of cups, the vendor sold large sodas for $0.70 each and small sodas for $0.50 each. The vendor knows two things; that a total of 1000 sodas were sold and has $580 total in sales. The vendor was too busy to keep track of how many sodas of each size sold. You need to show the vendor how to figure out how many of each size soda sold by using equations and explain how to solve the equations. The vendor has a very limited math background, but can pick up on how to do the math if it is explained in detail. Hint: this is like a coin or ticket problem, so be sure to set it up like one. Also, be very thorough in the explanation or the vendor will not understand.

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!

lets call the number of small sodas S
and the number of large sodas L
so: S%2BL=1000
and:.5S%2B.7L=580
solve s in the first equation:S=1000-L
plug s's value into 2nd equation.5%281000-L%29%2B.7L=580
solving for L 500-.5L%2B.7L=580----->.2L=80-->L=400
# of Large cups=400
# of small cups=1000-400=600