SOLUTION: How do I solve "Graph the equation" when the problem is x+y+2...Thanks, a confused Mom

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Question 166094: How do I solve "Graph the equation" when the problem is x+y+2...Thanks, a confused Mom
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Well the problem here is that there is no equation (it needs an equal sign "="). Is the problem supposed to be x%2By=2 ???


x%2By=2 Start with the given equation.


y=2-x Subtract x from both sides.


y=-x%2B2 Rearrange the terms.


Looking at y=-x%2B2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-1 and the y-intercept is b=2


Since b=2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -1, this means:

rise%2Frun=-1%2F1


which shows us that the rise is -1 and the run is 1. This means that to go from point to point, we can go down 1 and over 1



So starting at , go down 1 unit


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=-x%2B2

So this is the graph of y=-x%2B2 through the points and