Question 165016: f(x)=1/4(x+3)^2+8
find the vertex, the line of symmetry, and the maximum or minimum value of F(x). Graph the function.
Is this correct
vertex (-3,8)
line symmetry -3
Maximum/minimum value 8
Minimum
I do not know how to graph the function.
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! This site describes it quite nicely:
http://www.mathwarehouse.com/geometry/parabola/standard-and-vertex-form.php
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Standard vertex form of a parabola:
y= a(x-h)^2+k
.
Your problem:
f(x)=1/4(x+3)^2+8
find the vertex, the line of symmetry, and the maximum or minimum value of F(x). Graph the function.
.
Since 'a' is 1/4 (POSITIVE) -- since it is "positive" think of a "happy face" (a smile) indicating that the parabola opens upward (U) -- therefore, the vertex will be at the MINIMUM.
.
You had:
vertex (-3,8) (YES!)
line symmetry -3 (YES!)
Minimum value 8
.
As for graphing the parabola, this site describes it quite well:
http://a-s.clayton.edu/garrison/math%200099/parabola.htm
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