SOLUTION: Can you help me with some problems.I have a few of these problems maybe if you help me with this one i can figure out how to do the others.
Demand equation. Helen's Health Food
Algebra ->
Graphs
-> SOLUTION: Can you help me with some problems.I have a few of these problems maybe if you help me with this one i can figure out how to do the others.
Demand equation. Helen's Health Food
Log On
Question 151769: Can you help me with some problems.I have a few of these problems maybe if you help me with this one i can figure out how to do the others.
Demand equation. Helen's Health Food usually sells 400 can of ProPac Muscle Punch per week when the price is $55 per can. After experimenting with prices for some time. Helen has determined that the weekly demand can be found by using the equation
d=600-40p
where d is hte number ofcans and p isthe price per can.
a) WillHelen sell more or less Muscle Punch if she raises her price from $5 ?
b)What happens to her sales every time she raises her price by $1 ?
c) Graph the equation.
d) What is the maximum price hat she can charge and still sell at least one can? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Demand equation. Helen's Health Food usually sells 400 cans of ProPac Muscle Punch per week. when the price is $5 per can. After experimenting with prices for some time. Helen has determined that the weekly demand can be found by using the equation: d = 600 - 40p
where d is the number of cans
and p is the price per can.
:
a) Will Helen sell more or less Muscle Punch if she raises her price from $5?
You can see from the equation that, if the value of 40p increases,
the demand (d) decreases (sell less)
:
b)What happens to her sales every time she raises her price by $1 ?
Looking at the equation you can see that for each $1 increase in p you will sell 40 less cans
:
c) Graph the equation.
:
Plot the graph using the equation,
d on the y axis, p on the x axis:
Solve for d using: p = 0 and p = 10
The table
x | y
-------
0 |600
10 |200
Should look like this:
:
d) What is the maximum price hat she can charge and still sell at least one can?
d = 600 - 40p
Solve for p when d = 1
1 = 600 - 40p
40p = 600 - 1
40p = 599
p =
p = $14.975 is the max price (will sell one can)
;
Did this make sense to you, any questions?
