SOLUTION: I am having problems understanding the whole concept of graphing linear inequalities, for that matter, anything with graphing. Does anyone know where to get the rules for graphing?

Algebra ->  Graphs -> SOLUTION: I am having problems understanding the whole concept of graphing linear inequalities, for that matter, anything with graphing. Does anyone know where to get the rules for graphing?      Log On


   

Question 147191: I am having problems understanding the whole concept of graphing linear inequalities, for that matter, anything with graphing. Does anyone know where to get the rules for graphing? Or anything that goes step by step. I feel like a fool! But I'm not shy and I will ask if I need help. HELP!
Thanks for your time!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
It would help if you posted a particular problem, but I'll see what I can do.


Let's say that you want to graph the equation y=%281%2F2%29x%2B3



Looking at y=%281%2F2%29x%2B3 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=1%2F2 and the y-intercept is b=3


Since b=3 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 1%2F2, this means:

rise%2Frun=1%2F2


which shows us that the rise is 1 and the run is 2. This means that to go from point to point, we can go up 1 and over 2



So starting at , go up 1 unit


and to the right 2 units to get to the next point



Now draw a line through these points to graph y=%281%2F2%29x%2B3

So this is the graph of y=%281%2F2%29x%2B3 through the points and