SOLUTION: I am attempting to solve two equations using the substitution method.
x + y = 56 first equation
I have 3 times as many y as x, so I believe the next equation is
3x + y =
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-> SOLUTION: I am attempting to solve two equations using the substitution method.
x + y = 56 first equation
I have 3 times as many y as x, so I believe the next equation is
3x + y =
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Question 147127: I am attempting to solve two equations using the substitution method.
x + y = 56 first equation
I have 3 times as many y as x, so I believe the next equation is
3x + y = 56
solve for y
y = -3x + 56 now in the first equation, I replace y with -3x + 56
x + -3x +56 =56
-2x + 56 -56 = 56 -56
-2x = 0? This can not be correct. Can you help me?
Thank you very much.
You can put this solution on YOUR website! x + y = 56 first equation
I have 3 times as many y as x, so the next equation is
y = 3x
:
Substitute 3x for y in the 1st equation
x + 3x = 56
4x = 56
x =
x = 14
:
Does this explain it?
