Question 145727: How do you find the vertex, axis of symmetry and graph: f(x) -x^2-6x+3, in the back of my math book it says the vertex is (-3,12) i keep getting (-3,-6) Thanx :)
Found 3 solutions by stanbon, jim_thompson5910, Earlsdon: Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the vertex, axis of symmetry and graph: f(x)= -x^2-6x+3, in the back of my math book it says the vertex is (-3,12) i keep getting (-3,-6)
---------------
Vertex occurs where x = -b/2a = 6/-2 = -3
f(-3) = -(-3)^2-6(-3)+3 = -9+18+3 = 12
---------
Vertex at (-3,12)
Axis at x = -3
----------

Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): Answer by Earlsdon(6294) (Show Source):
|
|
|