SOLUTION: 10. Solve {{{abs((2x+1)/3)>5}}}

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Question 143741: 10. Solve abs%28%282x%2B1%29%2F3%29%3E5
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
abs%28%282x%2B1%29%2F3%29%3E5 Start with the given inequality


Break up the absolute value (remember, if you have abs%28x%29%3Ea, then x+%3C+-a or x+%3E+a)

%282x%2B1%29%2F3+%3C+-5 or %282x%2B1%29%2F3+%3E5 Break up the absolute value inequality using the given rule



cross%283%29%28%282x%2B1%29%2Fcross%283%29%29+%3C+3%28-5%29 or cross%283%29%28%282x%2B1%29%2Fcross%283%29%29+%3E+3%285%29 Multiply both sides by the LCD 3 to clear the fractions


2x%2B1+%3C+-15 or 2x%2B1+%3E+15 Distribute and multiply


x%3C+-8 or x+%3E+7 Isolate x in each case



So our solution is


x%3C+-8 or x+%3E+7



which looks like this in interval notation

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