SOLUTION: 7. Solve {{{system(x+3y-z = -2, 4x+6y+3z = 4, 2x-y+2z = 10)}}}
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-> SOLUTION: 7. Solve {{{system(x+3y-z = -2, 4x+6y+3z = 4, 2x-y+2z = 10)}}}
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Question 143738
:
7. Solve
Answer by
jim_thompson5910(35256)
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Equation 1
Equation 2
Equation 3
Multiply both sides of Equation 1 by 2
Distribute and multiply. Let's call this Equation 4
Now add Equation 4 to Equation 3 and call the result Equation 5
Equation 4
+
Equation 3
------------------
Equation 5
Multiply both sides of Equation 1 by 3
Distribute and multiply. Let's call this Equation 6
Now add Equation 5 to Equation 2 and call the result Equation 7
Equation 5
+
Equation 2
------------------
Equation 7
So we now have the two equations Equation 5 and Equation 7
Equation 5
Equation 7
Multiply both sides of Equation 5 by -3
Equation 7
Distribute
Equation 7
Now add the equations
+
---------------------------
Divide both sides of the resulting equation by -5 to isolate x
Reduce. So this is the first part of our answer.
Go back to Equation 7
Plug in
Multiply
Subtract 28 from both sides
Combine like terms on the right side
Divide both sides by 15 to isolate y
Reduce. So this is the second part of our answer.
Go back to Equation 1
Plug in
and
Multiply
Combine like terms on the left side
Add 2 to both sides
Combine like terms on the right side
Divide both sides by -1 to isolate z
Divide. So this is the third part of our answer.
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Answer:
So our answer is
,
and
which forms the point (4,-2,0)