SOLUTION: find the slope if it exists. There is a pic of a box with tiny squares inside the box and a line with (-5, 3) and (5, -2) do i just subtract the -5 and -2 and add the other 2?

Algebra ->  Graphs -> SOLUTION: find the slope if it exists. There is a pic of a box with tiny squares inside the box and a line with (-5, 3) and (5, -2) do i just subtract the -5 and -2 and add the other 2?       Log On


   

Question 134281: find the slope if it exists. There is a pic of a box with tiny squares inside the box and a line with (-5, 3) and (5, -2) do i just subtract the -5 and -2 and add the other 2?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Let's denote the first point (-5,3) as . In other words, and

Now let's denote the second point (5,-2) as . In other words, and



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m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula

m=%28-2-3%29%2F%285--5%29 Plug in y%5B2%5D=-2,y%5B1%5D=3,x%5B2%5D=5,x%5B1%5D=-5


m=-5%2F10 Subtract the terms in the numerator -2-3 to get -5. Subtract the terms in the denominator 5--5 to get 10

m=-1%2F2 Reduce


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Answer:

So the slope of the line through the points (-5,3) and (5,-2) is m=-1%2F2