SOLUTION: I'm having promblems understanding how to find the info i need to graph this equation..... I could possibly have the wrong equation. L x 15 -L ( this is the eqution I came up

Algebra ->  Graphs -> SOLUTION: I'm having promblems understanding how to find the info i need to graph this equation..... I could possibly have the wrong equation. L x 15 -L ( this is the eqution I came up      Log On


   



Question 133489This question is from textbook frogs, fleas, and painted cubes
: I'm having promblems understanding how to find the info i need to graph this equation.....
I could possibly have the wrong equation.
L x 15 -L ( this is the eqution I came up with)
the original equation is .... The rectangle has a perimeter of 30 meters and a side length of l, A=?
Thank you for your help
This question is from textbook frogs, fleas, and painted cubes

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
So far, so good.

A=L%2A%2815-L%29 is absolutely correct. But you probably want to put this into standard form:

A=-L%5E2%2B15L

This is just a quadratic in the form f%28x%29=ax%5E2%2Bbx%2Bc, substituting L for the independent variable x and with coefficients as follows:

a=-1
b=15
c=0

The vertex of the parabola has an x-coordinate at -b%2F2a, so -15%2F2%28-1%29=15%2F2

The y-coordinate of the vertex is equal to the value of the function at the x-coordinate, so -%2815%2F4%29%5E2%2B15%2815%2F2%29=-225%2F4%2B225%2F2=225%2F4

Hence the vertex of the graph is at (15/2,225/4).

Factors of -L%5E2%2B15L are L%2815-L%29, so zeroes of the polynomial are 0 and 15, meaning the x-intercepts are at (0,0) and (15,0).

Pick a couple other values for L:

If L = 1, then A=-%281%29%5E2%2B15%281%29=14, and by symmetry, if L = 14, A = 14

If L = 2, then A=-%282%29%5E2%2B15%282%29=26, and by symmetry, if L = 13, A = 26

Just plot the points and sketch a smooth curve.



Super-Double-Plus Extra Credit. Just looking at this picture, what specific quadrilateral gives the maximum area for a given perimeter?