SOLUTION: This is a Graph Question. I have to solve by graphing. What I got was (-1,-3), the thing is I didn't qraph it correctly. Any chance you can help me? *2x=y+1 2x-y=5* Pleas

Algebra ->  Graphs -> SOLUTION: This is a Graph Question. I have to solve by graphing. What I got was (-1,-3), the thing is I didn't qraph it correctly. Any chance you can help me? *2x=y+1 2x-y=5* Pleas      Log On


   

Question 129947This question is from textbook algebra
: This is a Graph Question. I have to solve by graphing. What I got was (-1,-3), the thing is I didn't qraph it correctly. Any chance you can help me?
*2x=y+1
2x-y=5*

Please and Thank You=) This question is from textbook algebra

Found 2 solutions by jim_thompson5910, Earlsdon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2x=y%2B1 Start with the first equation

2x-1=y Subtract 1 from both sides

y=2x-1 Rearrange the equation

Now let's graph the equation



Looking at y=2x-1 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=2 and the y-intercept is b=-1


Since b=-1 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 2, this means:

rise%2Frun=2%2F1


which shows us that the rise is 2 and the run is 1. This means that to go from point to point, we can go up 2 and over 1



So starting at , go up 2 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=2x-1

So this is the graph of y=2x-1 through the points and




2x-y=5 Now move onto the second equation

-y=5%2B2x Add 2x to both sides

-y=2x%2B5 Rearrange the terms

y=%282x%2B5%29%2F%28-1%29 Divide both sides by -1 to isolate y

y=-2x-5 Divide and simplify


Now let's graph the equation



Looking at y=-2x-5 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-2 and the y-intercept is b=-5


Since b=-5 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -2, this means:

rise%2Frun=-2%2F1


which shows us that the rise is -2 and the run is 1. This means that to go from point to point, we can go down 2 and over 1



So starting at , go down 2 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=-2x-5

So this is the graph of y=-2x-5 through the points and





Now let's graph y=2x-1 and y=-2x-5 together

Graph of y=2x-1 (red) and y=-2x-5 (green)


So here we can see that the two graphs intersect at the point (-1,-3)

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Hmmm...I wonder how you got any solution at all???
Let's write the equations in their slope-intercept form:
2x = y+1 ---> y = 2x-1
2x-y = 5 ---> y = 2x-5
You can immeditely see that the two equations represent parallel lines because their slopes are equal. Since parallel lines do not intersect, there is no solution to this syem of equation!
Let's look at their graphs.
graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C2x-1%2C2x-5%29
The answer to the problem then is: No solution!