SOLUTION: I need help with function notation. Not only do I not completely get the concept, I definitely don't understand graphing it. Thanks so much Graph f(x) = 3x + 2

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Question 126629: I need help with function notation. Not only do I not completely get the concept, I definitely don't understand graphing it. Thanks so much
Graph f(x) = 3x + 2

Found 2 solutions by solver91311, jim_thompson5910:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not sure whether you don't understand graphing, or you are having trouble because it says f%28x%29=3x%2B2 instead of y=3x%2B2.

Actually there is no difference between the two ways of expressing the relationship except to say that y=3x%2B2 only guarantees that you have a relationship that makes the value of y dependent on the value of x. (hence the terms dependent and independent variables). The function notation on the other hand guarantees that the relationship is, in fact, a function.

So, what's the diff? A relationship can be any rule that relates the two (or more) variables, but a function must have the property that for any given value of the independent variable (x in this case) for which the function is defined, there is one and only one value of the dependent variable (y) and therefore one and only one value for the function. Another way to look at it is that if the relationship is a function, then there is no possible vertical line that intersects the graph of the function in more than one place.

As a counter-example consider this relationship: x%5E2%2By%5E2=4. The graph of this relationship is a circle centered at the origin with a radius of 2. With two exceptions, every vertical line that intersects this graph at all intersects it in two points. Therefore, the relation is NOT a function. On the other hand, the relation y=sqrt%284-x%5E2%29 which is just the upper half of the same circle (y=-sqrt%284-x%5E2%29 would be the bottom half) IS a function because for all x in the domain of the function (-2%3C=x%3C=2, there is one and only one value of the function.

Since y=3x%2B2 is, in fact, a function, we can write y=f%28x%29=3x%2B2.

As to graphing when you are presented with a function in function notation, you can just rely on the equal relationship between y and f(x), or you can label the vertical axis on your graph as f(x) instead of the traditional y.

Since this is a 1st degree function (no term has an exponent greater than 1, and there are no xy terms), you should, by now, realize that your graph will be a straight line. Straight lines are determined by no more and no less than two points.

All you have to do is pick a value for x and evaluate the function at the selected value to determine one of the points, which is then (x,f(x)). Do this process twice, plot the points, and draw your line.

I usually like to pick values for x that make the arithmetic easy. Let's use 0 and 1.

f%280%29=3%280%29%2B2=2, so the first point is (0,2)

f%281%29=3%281%29%2B2=5, so the second point is (1,5)


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember, y is the same as f(x). So the function f%28x%29=3x%2B2 is equivalent to the equation y=3x%2B2




Looking at y=3x%2B2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=3 and the y-intercept is b=2


Since b=2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 3, this means:

rise%2Frun=3%2F1


which shows us that the rise is 3 and the run is 1. This means that to go from point to point, we can go up 3 and over 1



So starting at , go up 3 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=3x%2B2

So this is the graph of y=3x%2B2 through the points and