SOLUTION: A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200 mL of a 35% acid solution? please help just one more time lol thank you so much

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Question 125402: A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200 mL of a 35% acid solution?
please help just one more time lol thank you so much

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(acid from each solution) / (total amount of solution) = 35%
Let a= amount of 25% solution used
Let b= amount of 50% solution used
%28.25a+%2B+.5b%29+%2F+%28a+%2B+b%29+=+.35
also given is
a+%2B+b+=+200 ml
b+=+200+-+a
%28.25a+%2B+.5b%29+%2F+200+=+.35
%28.25a+%2B+.5%28200+-+a%29%29+%2F+200+=+.35
%28.25a+%2B+100+-+.5a%29+%2F+200+=+.35
%28-.25a+%2B+100%29+%2F+200+=+.35
-.25a+%2B+100+=+70
-.25a+=+-30
a+=+120
b+=+200+-+a
b+=+200+-+120
b+=+80
There are 120 ml of the 25% solution and 80 ml of the 50% solution
check answer
%28.25a+%2B+.5b%29+%2F+200+=+.35
%28.25%2A120+%2B+.5%2A80%29+%2F+200+=+.35
%2830+%2B+40%29+%2F+200+=+.35
7%2F20+=+.35
.35+=+.35
OK