SOLUTION: Jennifer has collected $4.50 in nickels and dimes. If she has 55 coins, how many of each kind of coin does she have? im confused i just cannot do word problems

Algebra ->  Graphs -> SOLUTION: Jennifer has collected $4.50 in nickels and dimes. If she has 55 coins, how many of each kind of coin does she have? im confused i just cannot do word problems      Log On


   

Question 125399: Jennifer has collected $4.50 in nickels and dimes. If she has 55 coins, how many of each kind of coin does she have?
im confused i just cannot do word problems
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let n = number of nickels
Let d = number of dimes
n+%2B+d+=+55
d+=+55+-+n
5n+%2B+10d+=+450
5n+%2B+10%2855+-+n%29+=+450
5n+%2B+550+-+10n+=+450
-5n+=+-100
n+=+20
d+=+55+-+n
d+=+35
There are 20 nickels and 35 dimes
check:
5n+%2B+10d+=+450
5%2A20+%2B+10%2A35+=+450
100+%2B+350+=+450
450+=+450
OK