SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

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Question 124935: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Answer by iluvbuilding429(41) About Me  (Show Source):
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The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.


You already know that L=2w+2. So, put this into the formula for perimeter:
52=2w%2B2%282w%2B2%29


Multiply:
52=2w%2B4w%2B4


Add:
52=6w%2B4


Subtract 4 from both sides:
48=6w


Divide both sides by 6:
8=w
Now you know the width. To find the length, use L=2w+2.
L=2%288%29%2B2


Multiply:
L=16%2B2


Add:
L=18


So, the length is 18, and the width is 8.