SOLUTION: Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the fuction gives a line with a

Algebra ->  Graphs -> SOLUTION: Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the fuction gives a line with a       Log On


   



Question 124396: Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the fuction gives a line with a slope of 0.12. The monthly cost of 30 minutes of calls is $12.63. What is the monthly cost for 21 minutes of calls?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I would graph minutes on the horizontal x axis
and monthly cost on the vertical y axis.
The equation for the line is y+=+.12x+%2B+b
12.63+=+.12%2A30+%2B+b
12.63+=+3.6+%2B+b
b+=+9.03
So the equation is y+=+.12x+%2B+9.03 where y is in
dollars and x is in minutes
y+=+.12%2A21+%2B+9.03
y+=+2.52+%2B+9.03
y+=+11.55
The monhly cost for 21 minutes is $11.55
(unless I made a mistake)