Question 123729: Please help me solve this problem:
Find an equation of the line containing the given point and having the given slope
(_3,0), m=-2
Found 2 solutions by sujanag, checkley71:
Answer by sujanag(3)   (Show Source):
You can put this solution on YOUR website! (x1, y1)= (-3,0)
Slope = m = -2
Slope = (x2 - x1)/ (y2 - y1)
Given Slope = -2
Then (x2 - x1)/ (y2 - y1)= -2
(x2 - (-3)) / (y2 - 0) = -2
x2 + 3 = -2 (y2 +0) ( By taking denominator to other side)
x2 + 3 = -2y2
By making into order, x+2y+3 = 0
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! Y=mX+b
0=-2*-3+b
0=6+b
b=-6 ANSWER FOR THE Y INTERCEPT.
Y=-2X-6 ANSWER FOR THE LINE THROUGH (-3,0) WITH A SLOPE=-2
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -2x -6).
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