Question 121730: I need to write an equation of a line containing point (4,-9) and parrellel to the line 6x-5y=7 Found 2 solutions by checkley71, MathLover1:Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! FIRST WE NEED TO FIND THE SLOPE OF THIS EQUATION.
6X-5Y=7
-5Y=-6X+7
Y=-6X/-5+7/-5
Y=6X/5-7/5 ( RED LINE) HERE THE SLOPE=6/5.
NOW REPLACE X & Y BY 4 & -9 ALONG WITH THE SLOPE=6/5 & SOLVE FOR THE Y INTERCEPT(b) IN THE LINE FORMULA [Y=mX+b]
-9=6/5*4+b
-9=24/5+b
b=-9-24/5
b=(-9*5-24)/5
b=(-45-24)/5
b=-69/5 OR
Y=6X/5-69/5 (GREEN LINE) (graph 300x300 pixels, x from -6 to 20, y from -15 to 15, of TWO functions y = 6x/5 -7/5 and y = 6x/5 -69/5).
Since any two parallel lines have the same slope we know the slope of the unknown line is (its from the slope of which is also ).
Also since the unknown line goes through (4,-9), we can find the equation by plugging in this info into the point-slope formula
Point-Slope Formula:
where m is the slope and (,) is the given point
Plug in , , and
Distribute
Multiply
Subtract from both sides to isolate y
Combine like terms
So the equation of the line that is parallel to and goes through (,) is
So here are the graphs of the equations and
graph of the given equation (red) and graph of the line (green) that is parallel to the given graph and goes through (,)