SOLUTION: Precalculus Chapter 1, section 1.2 Q. 42 The graph of an equation is given. The graph is a curve rising from quadrant 2 on the xy-plane through the point (0,1) and moving upw

Algebra ->  Graphs -> SOLUTION: Precalculus Chapter 1, section 1.2 Q. 42 The graph of an equation is given. The graph is a curve rising from quadrant 2 on the xy-plane through the point (0,1) and moving upw      Log On


   



Question 1210673: Precalculus
Chapter 1, section 1.2
Q. 42
The graph of an equation is given. The graph is a curve rising from quadrant 2 on the xy-plane through the point (0,1) and moving upward into quadrant 1.
A. Find the intercepts.
B. Indicate if the graph is symmetric with respect to the x-axis, y-axis, or the origin.

A.From the given picture, it looks like the curve will never cross the x-axis. I think the asymptote of the curve is the line y = 0. I say there are no x-intercepts. The curve does go through the point (0,1). The point (0,1) is the y-intercept, which can also be expressed as the line y = 1. You say?
I am not sure how to answer B.

Answer by the_limit_DNE(3) About Me  (Show Source):
You can put this solution on YOUR website!
A. Yes, the curve (exponential function) will not cross the x-axis and will have a horizontal asymptote of y=0. The y-intercept is (0, 1), however it cannot be expressed as y=1; y=1 is a horiziontal line, not a coordinate.
B. Since the graph is exponential, it is not symmetrical to the x-axis, y-axis, or the origin.