SOLUTION: write an equation of the line containing the point (6,-4) and perpendicular to the line y=-2x-3

Algebra ->  Graphs -> SOLUTION: write an equation of the line containing the point (6,-4) and perpendicular to the line y=-2x-3      Log On


   

Question 1208078: write an equation of the line containing the point (6,-4) and perpendicular to the line y=-2x-3
Found 2 solutions by josgarithmetic, timofer:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
------------
containing the point (6,-4) and perpendicular to the line y=-2x-3
-----------

Want slope 1%2F2.
To include the given point, -4=%281%2F2%29%2A6%2Bb;
-4-%286%2F2%29=b
b=-7
so the equation is highlight%28y=x%2F2-7%29.

Answer by timofer(104) About Me  (Show Source):
You can put this solution on YOUR website!
contain point (c,d) perpendicular to y=mx+b

want a slope m%2Ag=-1
g=-1%2Fm

Using given point, if (c,d)
y=%28-1%2Fm%29x%2Bb
d=-%281%2Fm%29c%2Bb
b=d%2B%281%2Fm%29c

Put it all together,
y=%281%2Fm%29x%2Bd%2Bc%2Fm
You can plug in the given numbers for the variables and get your specific equation.