Question 120588: How would I graph the following equations: (a) y = 1/3x + 1 (b) y = -3x + 1 (c) y = 3x + 1 (d) y = -1/3x + 1?
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website! Use the same procedure to graph any linear equation. I'll do one of them.
Select two values for x. It doesn't really matter which values you select, but I like small, easy to manipulate numbers like 0 and 1. Since these are linear equations, i.e. you get a straight line when you graph them, you only need to determine two points.
Once you have chosen your x values, evaluate the equation for each by substituting each of your chosen values for x and solving for y.
In your first problem, let x = 0.  . So if x is 0, y is 1, and one of the points on our line is (0,1). Now let x = 3. (I chose three because 3 is the denominator of the coefficient fraction)  . So if x is 3, y is 2, and another point on our line is (3,2).
Plot these two points on your graph. I've labeled them A and B
Now construct a straight line through the two points with a straight edge and you are done.
All you have to do is follow the same procedure for each of the other three problems.
John
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