SOLUTION: How do I find the y-intercept for -x + 3y = 15?

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Question 120501: How do I find the y-intercept for -x + 3y = 15?
Found 2 solutions by tutor_paul, bucky:
Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
How do I find the y-intercept for -x + 3y = 15?
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First, put the equation into y=mx+b form. Then, the slope is just the 'm' term.
-x%2B3y=15
3y=x%2B15
y=x%2F3%2B5
So, your slope is just the 'm' term, (the coefficient of x):
highlight%28m=1%2F3%29
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Good Luck,
tutor_paul@yahoo.com

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Think about a coordinate system. If a point is on the y-axis, what is its corresponding
x-value. You can see that any point on the y-axis has zero for its x-value.
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Therefore for the given equation, if you set the value of x at zero, the resulting value of y
will be the value on the y-axis where the intercept occurs. So ... start with:
.
-x + 3y = 15
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Set x equal to zero and the equation reduces to:
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3y = 15
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Solve for y by dividing both sides of this equation by 3 to get:
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y = 15/3 = 5
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The graph crosses the y-axis where the value of y is +5. You may also see the y intercept
given in the form of (x, y). So, from the discussion above, in this form the y-intercept
is expressed as (0, +5).
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The graph of the given equation looks like this:
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graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B15%29%2F3%29
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and you can see the y-intercept on this graph is at y = +5
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Hope this helps you to understand the problem a little better.
.