SOLUTION: 4(2y - 5) ≤ 5y - 2 and 9y - 1 > -1 Please add complete solution, thank you.

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Question 1202694: 4(2y - 5) ≤ 5y - 2 and 9y - 1 > -1
Please add complete solution, thank you.

Found 2 solutions by josgarithmetic, math_tutor2020:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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4(2y - 5) ≤ 5y - 2 and 9y - 1 > -1
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4%282y-5%29%3C=5y-2
8y-20%3C=5y-2
3y%3C=18
y%3C=6----------your first inequality, simplified

9y-1%3E-1
9y%3E0
y%3E0-----------your second inequality, simplified


Put those two inequalities together,
system%28y%3C=6%2Cy%3E0%29

Same as highlight%280%3Cy%3C=6%29, and you could show this on a number line if you want.

Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

As mentioned by the tutor @josgarithmetic, the answer is 0+%3C+y+%3C=+6
y is between 0 and 6 where we exclude 0 but include 6.
y = 0 isn't a solution, but y = 6 is a solution.

The interval notation would be (0, 6]
A parenthesis is used to exclude the endpoint. A square bracket is used to include the endpoint.

The graph on a number line will have an open hole at 0, a closed filled in circle at 6, with shading in between.
The open hole is to exclude the endpoint.