SOLUTION: Maximize:z=40x+12y Subject to: 6x-2y\le 9 3x+y\le 9 x\ge 0 y\ge 0

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Question 1202519: Maximize:z=40x+12y
Subject to:
6x-2y\le 9
3x+y\le 9
x\ge 0
y\ge 0

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
usng the desmos.com calculator at , you would graph the opposite of the cnstraint inequalities and evaluate the objective function the corner points of the feasible region.
the area of the graph not shaded is the region of feasibility.
the corner points of the feasible region will contain the maximum value of the objective function.
your maximum value is 117 at the corner point (2.25,2.25)
here's the graph.



all the contrains need to be satisfied at the corner point.
at ()2.25,2.25),...
6x - 2y <= 9 is satisfied.
3x + y <= 9 is also satisfied.